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本文涉及知识点
树上倍增 树 图论 并集查找 换根法 深度优先
割点原理及封装好的割点类(预计2024年3月11号左右发布)
LeetCode3067. 在带权树网络中统计可连接服务器对数目
给你一棵无根带权树,树中总共有 n 个节点,分别表示 n 个服务器,服务器从 0 到 n - 1 编号。同时给你一个数组 edges ,其中 edges[i] = [ai, bi, weighti] 表示节点 ai 和 bi 之间有一条双向边,边的权值为 weighti 。再给你一个整数 signalSpeed 。
如果两个服务器 a ,b 和 c 满足以下条件,那么我们称服务器 a 和 b 是通过服务器 c 可连接的 :
a < b ,a != c 且 b != c 。
从 c 到 a 的距离是可以被 signalSpeed 整除的。
从 c 到 b 的距离是可以被 signalSpeed 整除的。
从 c 到 b 的路径与从 c 到 a 的路径没有任何公共边。
请你返回一个长度为 n 的整数数组 count ,其中 count[i] 表示通过服务器 i 可连接 的服务器对的 数目 。
示例 1:
输入:edges = [[0,1,1],[1,2,5],[2,3,13],[3,4,9],[4,5,2]], signalSpeed = 1
输出:[0,4,6,6,4,0]
解释:由于 signalSpeed 等于 1 ,count[c] 等于所有从 c 开始且没有公共边的路径对数目。
在输入图中,count[c] 等于服务器 c 左边服务器数目乘以右边服务器数目。
示例 2:
输入:edges = [[0,6,3],[6,5,3],[0,3,1],[3,2,7],[3,1,6],[3,4,2]], signalSpeed = 3
输出:[2,0,0,0,0,0,2]
解释:通过服务器 0 ,有 2 个可连接服务器对(4, 5) 和 (4, 6) 。
通过服务器 6 ,有 2 个可连接服务器对 (4, 5) 和 (0, 5) 。
所有服务器对都必须通过服务器 0 或 6 才可连接,所以其他服务器对应的可连接服务器对数目都为 0 。
提示:
2 <= n <= 1000
edges.length == n - 1
edges[i].length == 3
0 <= ai, bi < n
edges[i] = [ai, bi, weighti]
1 <= weighti <= 106
1 <= signalSpeed <= 106
输入保证 edges 构成一棵合法的树。
树上倍增
本题有三个考点:
一,如何计算树上两个节点x1,x2的距离。
假定这两个节点的最早公共祖先是pub。以任意节点root为根,f(x)表示节点x到root的距离。
x1到x2的距离:f(x1)+f(x2)-2*f(pub)。
二,如何找到最早公共祖先:树上倍增。
记录各节点的1级祖先(父节点)、2级祖先、4级祖先…
三,如果判断ac和bc有公共边。
树是连通无向无环图,因为无环,所以两个节点的路径唯一。
假设公共边是x3x4。则x3到c的路径唯一,假定x3到c的倒数第二个端点是x5,则ab和bc的最后一条边都是 x 3 c → \overrightarrow{x3c} x3c。断开所以和c相连的边,如果a和b在同一个连通区域,则有公共边。用并查集看是否在同一个连通区域。
时间复杂度: O(nnlogn)。 枚举c,时间复杂度O(n);枚举ab,时间复杂度O(n)。查公共路径O(logn)。
并集查找
class CNeiBo { public: static vector<vector<int>> Two(int n, vector<vector<int>>& edges, bool bDirect, int iBase = 0) { vector<vector<int>> vNeiBo(n); for (const auto& v : edges) { vNeiBo[v[0] - iBase].emplace_back(v[1] - iBase); if (!bDirect) { vNeiBo[v[1] - iBase].emplace_back(v[0] - iBase); } } return vNeiBo; } static vector<vector<std::pair<int, int>>> Three(int n, vector<vector<int>>& edges, bool bDirect, int iBase = 0) { vector<vector<std::pair<int, int>>> vNeiBo(n); for (const auto& v : edges) { vNeiBo[v[0] - iBase].emplace_back(v[1] - iBase, v[2]); if (!bDirect) { vNeiBo[v[1] - iBase].emplace_back(v[0] - iBase, v[2]); } } return vNeiBo; } }; class CUnionFind { public: CUnionFind(int iSize) :m_vNodeToRegion(iSize) { for (int i = 0; i < iSize; i++) { m_vNodeToRegion[i] = i; } m_iConnetRegionCount = iSize; } CUnionFind(vector<vector<int>>& vNeiBo):CUnionFind(vNeiBo.size()) { for (int i = 0; i < vNeiBo.size(); i++) { for (const auto& n : vNeiBo[i]) { Union(i, n); } } } int GetConnectRegionIndex(int iNode) { int& iConnectNO = m_vNodeToRegion[iNode]; if (iNode == iConnectNO) { return iNode; } return iConnectNO = GetConnectRegionIndex(iConnectNO); } void Union(int iNode1, int iNode2) { const int iConnectNO1 = GetConnectRegionIndex(iNode1); const int iConnectNO2 = GetConnectRegionIndex(iNode2); if (iConnectNO1 == iConnectNO2) { return; } m_iConnetRegionCount--; if (iConnectNO1 > iConnectNO2) { UnionConnect(iConnectNO1, iConnectNO2); } else { UnionConnect(iConnectNO2, iConnectNO1); } } bool IsConnect(int iNode1, int iNode2) { return GetConnectRegionIndex(iNode1) == GetConnectRegionIndex(iNode2); } int GetConnetRegionCount()const { return m_iConnetRegionCount; } vector<int> GetNodeCountOfRegion()//各联通区域的节点数量 { const int iNodeSize = m_vNodeToRegion.size(); vector<int> vRet(iNodeSize); for (int i = 0; i < iNodeSize; i++) { vRet[GetConnectRegionIndex(i)]++; } return vRet; } std::unordered_map<int, vector<int>> GetNodeOfRegion() { std::unordered_map<int, vector<int>> ret; const int iNodeSize = m_vNodeToRegion.size(); for (int i = 0; i < iNodeSize; i++) { ret[GetConnectRegionIndex(i)].emplace_back(i); } return ret; } private: void UnionConnect(int iFrom, int iTo) { m_vNodeToRegion[iFrom] = iTo; } vector<int> m_vNodeToRegion;//各点所在联通区域的索引,本联通区域任意一点的索引,为了增加可理解性,用最小索引 int m_iConnetRegionCount; }; class CParents { public: CParents(vector<int>& vParent, const vector<int>& vLeve):m_vLeve(vLeve) { const int iMaxLeve = *std::max_element(vLeve.begin(), vLeve.end()); int iBitNum = 0; for (; (1 << iBitNum) < iMaxLeve; iBitNum++); const int n = vParent.size(); m_vParents.assign(iBitNum+1, vector<int>(n, -1)); m_vParents[0] = vParent; //树上倍增 for (int i = 1; i < m_vParents.size(); i++) { for (int j = 0; j < n; j++) { const int iPre = m_vParents[i - 1][j]; if (-1 != iPre) { m_vParents[i][j] = m_vParents[i - 1][iPre]; } } } } int GetParent(int iNode, int iLeve)const { int iParent = iNode; for (int iBit = 0; iBit < m_vParents.size(); iBit++) { if (-1 == iParent) { return iParent; } if (iLeve & (1 << iBit)) { iParent = m_vParents[iBit][iParent]; } } return iParent; } int GetPublicParent(int iNode1, int iNode2)const { int leve0 = m_vLeve[iNode1]; int leve1 = m_vLeve[iNode2]; if (leve0 < leve1) { iNode2 = GetParent(iNode2, leve1 - leve0); leve1 = leve0; } else { iNode1 = GetParent(iNode1, leve0 - leve1); leve0 = leve1; } //二分查找 int left = -1, r = leve0; while (r - left > 1) { const auto mid = left + (r - left) / 2; const int iParent0 = GetParent(iNode1, mid); const int iParent1 = GetParent(iNode2, mid); if (iParent0 == iParent1) { r = mid; } else { left = mid; } } return GetParent(iNode1, r); } protected: vector<vector<int>> m_vParents; const vector<int> m_vLeve; }; class Solution { public: vector<int> countPairsOfConnectableServers(vector<vector<int>>& edges, int signalSpeed) { m_c = edges.size() + 1; m_vDisToRoot.resize(m_c); m_vParent.resize(m_c); m_vLeve.resize(m_c); auto neiBo = CNeiBo::Three(m_c, edges, false, 0); DFS(neiBo, 0, -1, 0,0); CParents par(m_vParent,m_vLeve); vector<int> vRet(m_c); for (int c = 0; c < m_c; c++) { CUnionFind uf(m_c); for (const auto& v : edges) { if ((v[0] == c) || (v[1] == c)) { continue; } uf.Union(v[0], v[1]); } vector<int> vRegionCnt(m_c); for (int ab = 0; ab < m_c; ab++) { if (ab == c ) { continue; } const int pub = par.GetPublicParent(ab, c); const int len = m_vDisToRoot[ab] + m_vDisToRoot[c] - 2 * m_vDisToRoot[pub]; if (0 != len % signalSpeed) { continue; } vRegionCnt[uf.GetConnectRegionIndex(ab)]++; } int&iRet = vRet[c]; const int total = std::accumulate(vRegionCnt.begin(), vRegionCnt.end(), 0); for (int c1 = 0; c1 < m_c; c1++) { iRet += vRegionCnt[c1] * (total - vRegionCnt[c1]); } iRet /= 2; } return vRet; } void DFS(vector<vector<std::pair<int, int>>>& neiBo, int cur, int par,int leve,int dis) { m_vDisToRoot[cur] =dis; m_vParent[cur] = par; m_vLeve[cur] = leve; for (const auto& [next,len] : neiBo[cur]) { if (next == par) { continue; } DFS(neiBo, next, cur,leve+1,dis+len); } } vector<int> m_vDisToRoot,m_vParent,m_vLeve; int m_c; };
测试用例
template<class T,class T2> void Assert(const T& t1, const T2& t2) { assert(t1 == t2); } template<class T> void Assert(const vector<T>& v1, const vector<T>& v2) { if (v1.size() != v2.size()) { assert(false); return; } for (int i = 0; i < v1.size(); i++) { Assert(v1[i], v2[i]); } } int main() { vector<vector<int>> edges; int signalSpeed; { Solution sln; edges = { }, signalSpeed = 1; auto res = sln.countPairsOfConnectableServers(edges, signalSpeed); Assert({ 0 }, res); } { Solution sln; edges = { {0,1,1} }, signalSpeed = 1; auto res = sln.countPairsOfConnectableServers(edges, signalSpeed); Assert({ 0,0 }, res); } { Solution sln; edges = { {0,1,1},{1,2,1} }, signalSpeed = 1; auto res = sln.countPairsOfConnectableServers(edges, signalSpeed); Assert({ 0,1,0 }, res); } { Solution sln; edges = { {0,1,1},{1,2,5},{2,3,13},{3,4,9},{4,5,2} }, signalSpeed = 1; auto res = sln.countPairsOfConnectableServers(edges, signalSpeed); Assert({ 0,4,6,6,4,0 } , res); } { Solution sln; edges = { {0,6,3},{6,5,3},{0,3,1},{3,2,7},{3,1,6},{3,4,2} }, signalSpeed = 3; auto res = sln.countPairsOfConnectableServers(edges, signalSpeed); Assert({ 2,0,0,0,0,0,2 }, res); } }
换根法DFS
树中删除一个节点,则各孩子各一个连通区域,除自己及后代外一个区域。如果这个节点是根,则简单得多。各孩子一个连通区域。
DSF(cur) 返回自己及子孙到当前根节点距离是signalSpeed 倍的节点数量。令当前根节点各孩子的返回值是{i1,i2, ⋯ \cdots ⋯,im} 。i1*i2+(i1+i2)*i3 ⋯ \cdots ⋯ +(I1+i2+ … \dots … + i m − 1 _{m-1} m−1)*im。这样不必除以二。
a<b ,表示a !=b ,(a,b)和(b,a)只取一个。
class CNeiBo { public: static vector<vector<int>> Two(int n, vector<vector<int>>& edges, bool bDirect, int iBase = 0) { vector<vector<int>> vNeiBo(n); for (const auto& v : edges) { vNeiBo[v[0] - iBase].emplace_back(v[1] - iBase); if (!bDirect) { vNeiBo[v[1] - iBase].emplace_back(v[0] - iBase); } } return vNeiBo; } static vector<vector<std::pair<int, int>>> Three(int n, vector<vector<int>>& edges, bool bDirect, int iBase = 0) { vector<vector<std::pair<int, int>>> vNeiBo(n); for (const auto& v : edges) { vNeiBo[v[0] - iBase].emplace_back(v[1] - iBase, v[2]); if (!bDirect) { vNeiBo[v[1] - iBase].emplace_back(v[0] - iBase, v[2]); } } return vNeiBo; } }; class Solution { public: vector<int> countPairsOfConnectableServers(vector<vector<int>>& edges, int signalSpeed) { m_c = edges.size() + 1; m_iSignalSpeed = signalSpeed; auto neiBo = CNeiBo::Three(m_c, edges, false, 0); vector<int> vRet(m_c); for (int c = 0; c < m_c; c++) { int& iRet = vRet[c]; int left = 0; for (const auto& [next, len] : neiBo[c]) { int cur = DFS(neiBo, next, c, len); iRet += left * cur; left += cur; } } return vRet; } int DFS(vector<vector<std::pair<int, int>>>& neiBo, int cur, int par,int dis) { int iRet = (0 ==dis % m_iSignalSpeed); for (const auto& [next,len] : neiBo[cur]) { if (next == par) { continue; } iRet +=DFS(neiBo, next, cur,dis+len); } return iRet; } int m_iSignalSpeed; int m_c; };
割点
本解法过于复杂,除非用了提前封装好的割点扩展类,否则被使用。
class CNeiBo { public: static vector<vector<int>> Two(int n, vector<vector<int>>& edges, bool bDirect, int iBase = 0) { vector<vector<int>> vNeiBo(n); for (const auto& v : edges) { vNeiBo[v[0] - iBase].emplace_back(v[1] - iBase); if (!bDirect) { vNeiBo[v[1] - iBase].emplace_back(v[0] - iBase); } } return vNeiBo; } static vector<vector<std::pair<int, int>>> Three(int n, vector<vector<int>>& edges, bool bDirect, int iBase = 0) { vector<vector<std::pair<int, int>>> vNeiBo(n); for (const auto& v : edges) { vNeiBo[v[0] - iBase].emplace_back(v[1] - iBase, v[2]); if (!bDirect) { vNeiBo[v[1] - iBase].emplace_back(v[0] - iBase, v[2]); } } return vNeiBo; } }; class CUnionFind { public: CUnionFind(int iSize) :m_vNodeToRegion(iSize) { for (int i = 0; i < iSize; i++) { m_vNodeToRegion[i] = i; } m_iConnetRegionCount = iSize; } CUnionFind(vector<vector<int>>& vNeiBo):CUnionFind(vNeiBo.size()) { for (int i = 0; i < vNeiBo.size(); i++) { for (const auto& n : vNeiBo[i]) { Union(i, n); } } } int GetConnectRegionIndex(int iNode) { int& iConnectNO = m_vNodeToRegion[iNode]; if (iNode == iConnectNO) { return iNode; } return iConnectNO = GetConnectRegionIndex(iConnectNO); } void Union(int iNode1, int iNode2) { const int iConnectNO1 = GetConnectRegionIndex(iNode1); const int iConnectNO2 = GetConnectRegionIndex(iNode2); if (iConnectNO1 == iConnectNO2) { return; } m_iConnetRegionCount--; if (iConnectNO1 > iConnectNO2) { UnionConnect(iConnectNO1, iConnectNO2); } else { UnionConnect(iConnectNO2, iConnectNO1); } } bool IsConnect(int iNode1, int iNode2) { return GetConnectRegionIndex(iNode1) == GetConnectRegionIndex(iNode2); } int GetConnetRegionCount()const { return m_iConnetRegionCount; } vector<int> GetNodeCountOfRegion()//各联通区域的节点数量 { const int iNodeSize = m_vNodeToRegion.size(); vector<int> vRet(iNodeSize); for (int i = 0; i < iNodeSize; i++) { vRet[GetConnectRegionIndex(i)]++; } return vRet; } std::unordered_map<int, vector<int>> GetNodeOfRegion() { std::unordered_map<int, vector<int>> ret; const int iNodeSize = m_vNodeToRegion.size(); for (int i = 0; i < iNodeSize; i++) { ret[GetConnectRegionIndex(i)].emplace_back(i); } return ret; } private: void UnionConnect(int iFrom, int iTo) { m_vNodeToRegion[iFrom] = iTo; } vector<int> m_vNodeToRegion;//各点所在联通区域的索引,本联通区域任意一点的索引,为了增加可理解性,用最小索引 int m_iConnetRegionCount; }; class CParents { public: CParents(vector<int>& vParent, const int iMaxLeve) { int iBitNum = 0; for (; (1 << iBitNum) < iMaxLeve; iBitNum++); const int n = vParent.size(); m_vParents.assign(iBitNum+1, vector<int>(n, -1)); m_vParents[0] = vParent; //树上倍增 for (int i = 1; i < m_vParents.size(); i++) { for (int j = 0; j < n; j++) { const int iPre = m_vParents[i - 1][j]; if (-1 != iPre) { m_vParents[i][j] = m_vParents[i - 1][iPre]; } } } } int GetParent(int iNode, int iLeve)const { int iParent = iNode; for (int iBit = 0; iBit < m_vParents.size(); iBit++) { if (-1 == iParent) { return iParent; } if (iLeve & (1 << iBit)) { iParent = m_vParents[iBit][iParent]; } } return iParent; } protected: vector<vector<int>> m_vParents; }; class C2Parents : CParents { public: C2Parents(vector<int>& vParent, const vector<int>& vLeve) :m_vLeve(vLeve) , CParents(vParent,*std::max_element(vLeve.begin(), vLeve.end())) { } int GetPublicParent(int iNode1, int iNode2)const { int leve0 = m_vLeve[iNode1]; int leve1 = m_vLeve[iNode2]; if (leve0 < leve1) { iNode2 = GetParent(iNode2, leve1 - leve0); leve1 = leve0; } else { iNode1 = GetParent(iNode1, leve0 - leve1); leve0 = leve1; } //二分查找 int left = -1, r = leve0; while (r - left > 1) { const auto mid = left + (r - left) / 2; const int iParent0 = GetParent(iNode1, mid); const int iParent1 = GetParent(iNode2, mid); if (iParent0 == iParent1) { r = mid; } else { left = mid; } } return GetParent(iNode1, r); } protected: vector<vector<int>> m_vParents; const vector<int> m_vLeve; }; class CCutPointEx { public: CCutPointEx(const vector<vector<int>>& vNeiB) : m_iSize(vNeiB.size()) { m_vNodeToTime.assign(m_iSize, -1); m_vChildFirstEnd.resize(m_iSize); m_vNodeToRegion.assign(m_iSize, -1); m_vCut.assign(m_iSize, false); for (int i = 0; i < m_iSize; i++) { if (-1 != m_vNodeToTime[i]) { continue; } dfs(i, -1, vNeiB); m_iRegionCount++; } m_vTimeToNode.resize(m_iSize); for (int i = 0; i < m_iSize; i++) { m_vTimeToNode[m_vNodeToTime[i]] = i;; } } bool Visit(int src, int dest, int iCut)const { if (m_vNodeToRegion[src] != m_vNodeToRegion[dest]) { return false;//不在一个连通区域 } if (!m_vCut[iCut]) { return true; } const int r1 = GetCutRegion(iCut, src); const int r2 = GetCutRegion(iCut, dest); return r1 == r2; } vector<vector<int>> GetSubRegionOfCut(const int iCut)const {//删除iCut及和它相连的边后,iCut所在的区域会分成几个区域:父节点一个区域、各子节点一个区域 //父节点所在区域可能为空,如果iCut所在的连通区域只有一个节点,则返回一个没有节点的区域。 const auto& v = m_vChildFirstEnd[iCut]; vector<vector<int>> vRet(1); int j = 0; for (int iTime=0;iTime < m_iSize; iTime++ ) { const int iNode = m_vTimeToNode[iTime]; if ((j < v.size()) && ( iTime >= v[j].first )) { j++; vRet.emplace_back(); } if ((iCut != iNode) && (m_vNodeToRegion[iNode] == m_vNodeToRegion[iCut])) { if (v.size()&&(iTime >= v.back().second)) { vRet[0].emplace_back(iNode); } else { vRet.back().emplace_back(iNode); } } } return vRet; } protected: int dfs(int cur, int parent, const vector<vector<int>>& vNeiB) { auto& curTime = m_vNodeToTime[cur]; m_vNodeToRegion[cur] = m_iRegionCount; curTime = m_iTime++; int iCutChild = 0; int iMinTime = curTime; for (const auto& next : vNeiB[cur]) { if (-1 != m_vNodeToTime[next]) { iMinTime = min(iMinTime, m_vNodeToTime[next]); continue; } int iChildBeginTime = m_iTime; const int iChildMinTime = dfs(next, cur, vNeiB); iMinTime = min(iMinTime, iChildMinTime); if (iChildMinTime >= curTime) { iCutChild++; m_vChildFirstEnd[cur].push_back({ iChildBeginTime,m_iTime }); }; } m_vCut[cur] = (iCutChild + (-1 != parent)) >= 2; return iMinTime; } int GetCutRegion(int iCut, int iNode)const { const auto& v = m_vChildFirstEnd[iCut]; auto it = std::upper_bound(v.begin(), v.end(), m_vNodeToTime[iNode], [](int time, const std::pair<int, int>& pr) {return time < pr.first; }); if (v.begin() == it) { return v.size(); } --it; return (it->second > m_vNodeToTime[iNode]) ? (it - v.begin()) : v.size(); } int m_iTime = 0; const int m_iSize;//时间戳 int m_iRegionCount = 0; vector<int> m_vNodeToTime;//各节点到达时间,从0开始。 -1表示未处理 vector<bool> m_vCut;//是否是割点 vector<int> m_vNodeToRegion;//各节点所在区域 vector<vector<pair<int, int>>> m_vChildFirstEnd;//左闭右开空间[0,m_vChildFirstEnd[0].first)和[m_vChildFirstEnd.back().second,iSize)是一个区域 vector<int> m_vTimeToNode; };
2024年3月9号 新封装
class CNeiBo { public: static vector<vector<int>> Two(int n, vector<vector<int>>& edges, bool bDirect, int iBase = 0) { vector<vector<int>> vNeiBo(n); for (const auto& v : edges) { vNeiBo[v[0] - iBase].emplace_back(v[1] - iBase); if (!bDirect) { vNeiBo[v[1] - iBase].emplace_back(v[0] - iBase); } } return vNeiBo; } static vector<vector<std::pair<int, int>>> Three(int n, vector<vector<int>>& edges, bool bDirect, int iBase = 0) { vector<vector<std::pair<int, int>>> vNeiBo(n); for (const auto& v : edges) { vNeiBo[v[0] - iBase].emplace_back(v[1] - iBase, v[2]); if (!bDirect) { vNeiBo[v[1] - iBase].emplace_back(v[0] - iBase, v[2]); } } return vNeiBo; } }; class CUnionFind { public: CUnionFind(int iSize) :m_vNodeToRegion(iSize) { for (int i = 0; i < iSize; i++) { m_vNodeToRegion[i] = i; } m_iConnetRegionCount = iSize; } CUnionFind(vector<vector<int>>& vNeiBo):CUnionFind(vNeiBo.size()) { for (int i = 0; i < vNeiBo.size(); i++) { for (const auto& n : vNeiBo[i]) { Union(i, n); } } } int GetConnectRegionIndex(int iNode) { int& iConnectNO = m_vNodeToRegion[iNode]; if (iNode == iConnectNO) { return iNode; } return iConnectNO = GetConnectRegionIndex(iConnectNO); } void Union(int iNode1, int iNode2) { const int iConnectNO1 = GetConnectRegionIndex(iNode1); const int iConnectNO2 = GetConnectRegionIndex(iNode2); if (iConnectNO1 == iConnectNO2) { return; } m_iConnetRegionCount--; if (iConnectNO1 > iConnectNO2) { UnionConnect(iConnectNO1, iConnectNO2); } else { UnionConnect(iConnectNO2, iConnectNO1); } } bool IsConnect(int iNode1, int iNode2) { return GetConnectRegionIndex(iNode1) == GetConnectRegionIndex(iNode2); } int GetConnetRegionCount()const { return m_iConnetRegionCount; } vector<int> GetNodeCountOfRegion()//各联通区域的节点数量 { const int iNodeSize = m_vNodeToRegion.size(); vector<int> vRet(iNodeSize); for (int i = 0; i < iNodeSize; i++) { vRet[GetConnectRegionIndex(i)]++; } return vRet; } std::unordered_map<int, vector<int>> GetNodeOfRegion() { std::unordered_map<int, vector<int>> ret; const int iNodeSize = m_vNodeToRegion.size(); for (int i = 0; i < iNodeSize; i++) { ret[GetConnectRegionIndex(i)].emplace_back(i); } return ret; } private: void UnionConnect(int iFrom, int iTo) { m_vNodeToRegion[iFrom] = iTo; } vector<int> m_vNodeToRegion;//各点所在联通区域的索引,本联通区域任意一点的索引,为了增加可理解性,用最小索引 int m_iConnetRegionCount; }; class CParents { public: CParents(vector<int>& vParent, const int iMaxLeve) { int iBitNum = 0; for (; (1 << iBitNum) < iMaxLeve; iBitNum++); const int n = vParent.size(); m_vParents.assign(iBitNum+1, vector<int>(n, -1)); m_vParents[0] = vParent; //树上倍增 for (int i = 1; i < m_vParents.size(); i++) { for (int j = 0; j < n; j++) { const int iPre = m_vParents[i - 1][j]; if (-1 != iPre) { m_vParents[i][j] = m_vParents[i - 1][iPre]; } } } } int GetParent(int iNode, int iLeve)const { int iParent = iNode; for (int iBit = 0; iBit < m_vParents.size(); iBit++) { if (-1 == iParent) { return iParent; } if (iLeve & (1 << iBit)) { iParent = m_vParents[iBit][iParent]; } } return iParent; } protected: vector<vector<int>> m_vParents; }; class C2Parents : CParents { public: C2Parents(vector<int>& vParent, const vector<int>& vLeve) :m_vLeve(vLeve) , CParents(vParent,*std::max_element(vLeve.begin(), vLeve.end())) { } int GetPublicParent(int iNode1, int iNode2)const { int leve0 = m_vLeve[iNode1]; int leve1 = m_vLeve[iNode2]; if (leve0 < leve1) { iNode2 = GetParent(iNode2, leve1 - leve0); leve1 = leve0; } else { iNode1 = GetParent(iNode1, leve0 - leve1); leve0 = leve1; } //二分查找 int left = -1, r = leve0; while (r - left > 1) { const auto mid = left + (r - left) / 2; const int iParent0 = GetParent(iNode1, mid); const int iParent1 = GetParent(iNode2, mid); if (iParent0 == iParent1) { r = mid; } else { left = mid; } } return GetParent(iNode1, r); } protected: vector<vector<int>> m_vParents; const vector<int> m_vLeve; }; //割点 class CCutPoint { public: CCutPoint(const vector<vector<int>>& vNeiB) : m_iSize(vNeiB.size()) { m_vNodeToTime.assign(m_iSize, -1); m_vCutNewRegion.resize(m_iSize); for (int i = 0; i < m_iSize; i++) { if (-1 == m_vNodeToTime[i]) { m_vRegionFirstTime.emplace_back(m_iTime); dfs(vNeiB, i, -1); } } } int dfs(const vector<vector<int>>& vNeiB,const int cur, const int parent) { int iMinTime = m_vNodeToTime[cur] = m_iTime++; int iRegionCount = (-1 != parent);//根连通区域数量 for (const auto& next : vNeiB[cur]) { if (-1 != m_vNodeToTime[next]) { iMinTime = min(iMinTime, m_vNodeToTime[next]); continue; } const int childMinTime = dfs(vNeiB, next, cur); iMinTime = min(iMinTime, childMinTime); if (childMinTime >= m_vNodeToTime[cur]) { iRegionCount++; m_vCutNewRegion[cur].emplace_back(m_vNodeToTime[next], m_iTime); } } if (iRegionCount < 2) { m_vCutNewRegion[cur].clear(); } return iMinTime; } const int m_iSize; const vector<int>& Time()const { return m_vNodeToTime; }//各节点的时间戳 const vector<int>& RegionFirstTime()const { return m_vRegionFirstTime; }//各连通区域的最小时间戳 vector<bool> Cut()const { vector<bool> ret; for (int i = 0; i < m_iSize; i++) { ret.emplace_back(m_vCutNewRegion[i].size()); } return ret; }// const vector < vector<pair<int, int>>>& NewRegion()const { return m_vCutNewRegion; }; protected: vector<int> m_vNodeToTime; vector<int> m_vRegionFirstTime; vector < vector<pair<int, int>>> m_vCutNewRegion; //m_vCutNewRegion[c]如果存在[left,r) 表示割掉c后,时间戳[left,r)的节点会形成新区域 int m_iTime = 0; }; class CConnectAfterCutPoint { public: CConnectAfterCutPoint(const vector<vector<int>>& vNeiB) :m_ct(vNeiB) { m_vTimeToNode.resize(m_ct.m_iSize); m_vNodeToRegion.resize(m_ct.m_iSize); for (int iNode = 0; iNode < m_ct.m_iSize; iNode++) { m_vTimeToNode[m_ct.Time()[iNode]] = iNode; } for (int iTime = 0,iRegion= 0; iTime < m_ct.m_iSize; iTime++) { if ((iRegion < m_ct.RegionFirstTime().size()) && (m_ct.RegionFirstTime()[iRegion] == iTime)) { iRegion++; } m_vNodeToRegion[m_vTimeToNode[iTime]] = (iRegion - 1); } } bool Connect(int src, int dest, int iCut)const { if (m_vNodeToRegion[src] != m_vNodeToRegion[dest]) { return false;//不在一个连通区域 } if (0 == m_ct.NewRegion()[iCut].size()) {//不是割点 return true; } const int r1 = GetCutRegion(iCut, src); const int r2 = GetCutRegion(iCut, dest); return r1 == r2; } vector<vector<int>> GetSubRegionOfCut(const int iCut)const {//删除iCut及和它相连的边后,iCut所在的区域会分成几个区域:父节点一个区域、各子节点 一个区域 //父节点所在区域可能为空,如果iCut所在的连通区域只有一个节点,则返回一个没有节点的 区域。 const auto& v = m_ct.NewRegion()[iCut]; vector<int> vParen; const int iRegion = m_vNodeToRegion[iCut]; const int iEndTime = (iRegion + 1 == m_ct.RegionFirstTime().size()) ? m_ct.m_iSize : m_ct.RegionFirstTime()[iRegion+1]; vector<vector<int>> vRet; for (int iTime = m_ct.RegionFirstTime()[iRegion],j=-1; iTime < iEndTime; iTime++) { if (iCut == m_vTimeToNode[iTime]) { continue; } if ((j + 1 < v.size()) && (v[j + 1].first == iTime)) { j++; vRet.emplace_back(); } const int iNode = m_vTimeToNode[iTime]; if ((-1 != j ) && (iTime >= v[j].first) && (iTime < v[j].second)) { vRet.back().emplace_back(iNode); } else { vParen.emplace_back(iNode); } } vRet.emplace_back(); vRet.back().swap(vParen); return vRet; } protected: int GetCutRegion(int iCut, int iNode)const { const auto& v = m_ct.NewRegion()[iCut]; auto it = std::upper_bound(v.begin(), v.end(), m_ct.Time()[iNode], [](int time, const std::pair<int, int>& pr) {return time < pr.first; }); if (v.begin() == it) { return v.size(); } --it; return (it->second > m_ct.Time()[iNode]) ? (it - v.begin()) : v.size(); } vector<int> m_vTimeToNode; vector<int> m_vNodeToRegion;//各节点所在区域 const CCutPoint m_ct; }; class Solution { public: vector<int> countPairsOfConnectableServers(vector<vector<int>>& edges, int signalSpeed) { m_c = edges.size() + 1; m_vDisToRoot.resize(m_c); m_vParent.resize(m_c); m_vLeve.resize(m_c); auto neiBo = CNeiBo::Three(m_c, edges, false, 0); DFS(neiBo, 0, -1, 0, 0); C2Parents par(m_vParent, m_vLeve); auto neiBo2 = CNeiBo::Two(m_c, edges, false, 0); CConnectAfterCutPoint cut(neiBo2); vector<int> vRet(m_c); for (int c = 0; c < m_c; c++) { auto regs = cut.GetSubRegionOfCut(c); int left = 0; int& iRet = vRet[c]; for (const auto& subRegion : regs) { int cur = 0; for (const auto& ab : subRegion) { const int pub = par.GetPublicParent(ab, c); const int len = m_vDisToRoot[ab] + m_vDisToRoot[c] - 2 * m_vDisToRoot[pub]; if (0 != len % signalSpeed) { continue; } cur++; } iRet += left * cur; left += cur; } } return vRet; } void DFS(vector<vector<std::pair<int, int>>>& neiBo, int cur, int par, int leve, int dis) { m_vDisToRoot[cur] = dis; m_vParent[cur] = par; m_vLeve[cur] = leve; for (const auto& [next, len] : neiBo[cur]) { if (next == par) { continue; } DFS(neiBo, next, cur, leve + 1, dis + len); } } vector<int> m_vDisToRoot, m_vParent, m_vLeve; int m_c; };
DFS代替树上倍增
时间复杂度的瓶颈在 树上倍增。可以直接DFS 最近公共祖先。
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视频课程
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https://download.csdn.net/download/he_zhidan/88348653
我想对大家说的话 |
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闻缺陷则喜是一个美好的愿望,早发现问题,早修改问题,给老板节约钱。 |
子墨子言之:事无终始,无务多业。也就是我们常说的专业的人做专业的事。 |
如果程序是一条龙,那算法就是他的是睛 |
测试环境
操作系统:win7 开发环境: VS2019 C++17
或者 操作系统:win10 开发环境: VS2022 **C+
+17**
如无特殊说明,本算法用**C++**实现。