c# litjson如何解析复杂JSON结构

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筋斗云
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在C#中,可以使用LitJSON库来解析复杂的JSON结构。以下是一个简单的示例代码,演示如何使用LitJSON解析一个包含嵌套结构和数组的JSON:

using LitJson; using System;  class Program {     static void Main()     {         string json = @"         {             ""name"": ""John Smith"",             ""age"": 30,             ""isMarried"": true,             ""children"": [                 {                     ""name"": ""Alice"",                     ""age"": 5                 },                 {                     ""name"": ""Bob"",                     ""age"": 3                 }             ],             ""address"": {                 ""street"": ""123 Main St"",                 ""city"": ""New York"",                 ""zipCode"": ""10001""             }         }";          JsonData data = JsonMapper.ToObject(json);          string name = (string)data["name"];         int age = (int)data["age"];         bool isMarried = (bool)data["isMarried"];          JsonData children = data["children"];         foreach (JsonData child in children)         {             string childName = (string)child["name"];             int childAge = (int)child["age"];             Console.WriteLine("Child: {0} ({1} years old)", childName, childAge);         }          JsonData address = data["address"];         string street = (string)address["street"];         string city = (string)address["city"];         string zipCode = (string)address["zipCode"];          Console.WriteLine("Name: {0}", name);         Console.WriteLine("Age: {0}", age);         Console.WriteLine("Married: {0}", isMarried);         Console.WriteLine("Address: {0}, {1}, {2}", street, city, zipCode);     } } 

在这个示例中,首先将JSON字符串转换为JsonData对象,然后通过索引访问对象的属性和数组元素,从而获取JSON中的数据。通过递归访问嵌套结构和数组,可以方便地解析复杂的JSON数据。

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