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在Python中实现树的平衡可以通过实现平衡二叉树（AVL树）来实现。AVL树是一种自平衡二叉搜索树，即树的每个节点的左子树和右子树的高度差不超过1。
下面是一个简单的Python实现：
class TreeNode: def __init__(self, key): self.key = key self.left = None self.right = None self.height = 1 class AVLTree: def getHeight(self, node): if not node: return 0 return node.height def getBalance(self, node): if not node: return 0 return self.getHeight(node.left) - self.getHeight(node.right) def rotateRight(self, y): x = y.left T = x.right x.right = y y.left = T y.height = 1 + max(self.getHeight(y.left), self.getHeight(y.right)) x.height = 1 + max(self.getHeight(x.left), self.getHeight(x.right)) return x def rotateLeft(self, x): y = x.right T = y.left y.left = x x.right = T x.height = 1 + max(self.getHeight(x.left), self.getHeight(x.right)) y.height = 1 + max(self.getHeight(y.left), self.getHeight(y.right)) return y def insert(self, root, key): if not root: return TreeNode(key) elif key < root.key: root.left = self.insert(root.left, key) else: root.right = self.insert(root.right, key) root.height = 1 + max(self.getHeight(root.left), self.getHeight(root.right)) balance = self.getBalance(root) if balance > 1 and key < root.left.key: return self.rotateRight(root) if balance < -1 and key > root.right.key: return self.rotateLeft(root) if balance > 1 and key > root.left.key: root.left = self.rotateLeft(root.left) return self.rotateRight(root) if balance < -1 and key < root.right.key: root.right = self.rotateRight(root.right) return self.rotateLeft(root) return root 使用上述代码可以创建一个AVL树，然后通过调用insert方法向树中插入新节点，保持树的平衡。
