c++ complex类的运算符重载如何实现

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筋斗云
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在C++中,std::complex是一个模板类,用于表示复数。它已经为你提供了一系列运算符重载,例如+-*/,以及相等和不等运算符。然而,如果你想要自定义一个复数类并实现这些运算符重载,以下是一个简单的示例:

#include<iostream>  class Complex { public:     Complex(double real, double imag) : real_(real), imag_(imag) {}      // Getters     double real() const { return real_; }     double imag() const { return imag_; }      // Operator overloads     Complex operator+(const Complex& other) const {         return Complex(real_ + other.real_, imag_ + other.imag_);     }      Complex operator-(const Complex& other) const {         return Complex(real_ - other.real_, imag_ - other.imag_);     }      Complex operator*(const Complex& other) const {         double real_part = real_ * other.real_ - imag_ * other.imag_;         double imag_part = real_ * other.imag_ + imag_ * other.real_;         return Complex(real_part, imag_part);     }      Complex operator/(const Complex& other) const {         double denominator = other.real_ * other.real_ + other.imag_ * other.imag_;         double real_part = (real_ * other.real_ + imag_ * other.imag_) / denominator;         double imag_part = (imag_ * other.real_ - real_ * other.imag_) / denominator;         return Complex(real_part, imag_part);     }      bool operator==(const Complex& other) const {         return real_ == other.real_ && imag_ == other.imag_;     }      bool operator!=(const Complex& other) const {         return !(*this == other);     }  private:     double real_;     double imag_; };  int main() {     Complex a(3, 4);     Complex b(1, 2);      Complex c = a + b;     Complex d = a - b;     Complex e = a * b;     Complex f = a / b;      std::cout << "a + b = (" << c.real() << ", " << c.imag() << ")\n";     std::cout << "a - b = (" << d.real() << ", " << d.imag() << ")\n";     std::cout << "a * b = (" << e.real() << ", " << e.imag() << ")\n";     std::cout << "a / b = (" << f.real() << ", " << f.imag() << ")\n";      return 0; } 

这个示例中的Complex类实现了加法、减法、乘法和除法运算符重载。同时还实现了相等和不等运算符重载。注意,这里的运算符重载函数都是const成员函数,因为它们不应该修改对象的状态。

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